P₀ = tinggi bola awal = 3 m
S = tinggi setelah pantulan = ⅗ kali dari tinggi awal
*f(N) = P₀(S)ᴺ
f(1) = 3(⅗)¹
f(1) = 3(⅗) = 1,8 m
*f(N) = P₀(S)ᴺ
f(2) = 3(⅗)²
f(2) = 3(0,36) = 1,08 m
*f(N) = P₀(S)ᴺ
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Rabu, 15 Mei 2024 -
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P₀ = tinggi bola awal = 3 m
S = tinggi setelah pantulan = ⅗ kali dari tinggi awal
*f(N) = P₀(S)ᴺ
f(1) = 3(⅗)¹
f(1) = 3(⅗) = 1,8 m
*f(N) = P₀(S)ᴺ
f(2) = 3(⅗)²
f(2) = 3(0,36) = 1,08 m
*f(N) = P₀(S)ᴺ
Editor: Muhammad Suria
