Kunci Jawaban Matematika Kelas 9 Halaman 264 - 267 Uji Kompetensi 4 Hal 261 Kekongruenan dan Kesebangunan

AB/EF = CB/CF
AB/6 = (4+3)/4
AB = 7/4 x 6
AB = 42/4 = 10,5 cm

c. ΔACB ∼ ΔECF

CE/CA = EF/AB
CE/9 = 2/6
CE = 1/3 x 9
CE = 3 cm

CE = CA - CE = 9 - 3 = 6 cm

d. ΔACB ∼ ΔECF

CF/CB = EF/AB
CF/(FB+CF) = 5/7
CF/(4+CF) = 5/7
CF = 5/7 x (4+CF)
CF = 20/7 + 5/7 CF
CF - 5/7 CF = 20/7
2/7 CF = 20/7
CF = 20/7 x 7/2
CF = 10 cm

Baca Juga: Kunci Jawaban Metematika Kelas 9 Halaman 226 227 228 Semester 2 dan Cara Latihan 4.2 Kekongruenan Dua Segitiga

e. ΔAEC ∼ ΔDBC

AE/BD = CE/BC
AE/6 = 14/7
AE = 2 x 6 = 12 cm

f. EF = (DFxAB + FAxDC)/(DF+FA)
EF = (6x8 + 3x2)/(6+3)
EF = (48 + 6)/9
EF = 54/9 = 6 cm