i) (10⁶ . 4²)/(25³ . 8³)
= ((2.5)⁶ . (2²)²)/((5²)³ . (2³)³)
= (2⁶ . 5⁶ . 2⁴)/(5⁶ . 2⁹)
= (2⁶⁺⁴. 5⁶)/(5⁶ . 2⁹)
= (2¹⁰. 5⁶)/(5⁶ . 2⁹)
= (2¹⁰⁻⁹. 5⁶⁻⁶)
= 2¹ . 5⁰ = 2 . 1 = 2
j) (21⁵/9²) : (7/2)²
= [(3.7)⁵/(3²)²] : (7/2)²
i) (10⁶ . 4²)/(25³ . 8³)
= ((2.5)⁶ . (2²)²)/((5²)³ . (2³)³)
= (2⁶ . 5⁶ . 2⁴)/(5⁶ . 2⁹)
= (2⁶⁺⁴. 5⁶)/(5⁶ . 2⁹)
= (2¹⁰. 5⁶)/(5⁶ . 2⁹)
= (2¹⁰⁻⁹. 5⁶⁻⁶)
= 2¹ . 5⁰ = 2 . 1 = 2
j) (21⁵/9²) : (7/2)²
= [(3.7)⁵/(3²)²] : (7/2)²
Editor: Aziz Abdillah